(x+3)^2-4(x+3)=0

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Solution for (x+3)^2-4(x+3)=0 equation: 



(x+3)^2-4(x+3)=0

We multiply parentheses

(x+3)^2-4x-12=0

We add all the numbers together, and all the variables

-4x+(x+3)^2-12=0

We move all terms containing x to the left, all other terms to the right

-4x+(x+3)^2=12

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